James asked in Science & MathematicsChemistry · 9 years ago

# If a mixture of acid and water is supposed to be 6 to 1?

and you only need 4 gallons total solution. How many gallons acid and how many gallons water are needed?

Update:

What if you only need 3 gallons total solution: Then how many gallons acid and gallons water are needed?

Update 2:

What if you only needed 3/4 of a gallon of total solution?

Relevance
• C6H6
Lv 5
9 years ago

Question 1)

6 : 1 = 6

6 +1 = 7

4*6/7 = 24/7 = 3.43 gal of acid

4*1/7 = 0.57...........gal of water

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Total..............4......gal of solution

Check: 3.43 : 0.57 = 6 Ok!

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Question 2)

3 : 4 = 0.75

0.75*3.43 = 2.57 gal of acid

0.75*0.57 = 0.43 gal of acid

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Total……=...3.00.gal of solution

Check: 2.57: 0.43 = 6 approx Ok!

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Question 3)

3 : 4 = 0.75

0.75/3 = 0.25

0.25*2.57 = 0.64..........gal of acid

0.25*0.43 = 0.11..........gal of acid

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Total…....= 0.75 = 3/4 gal of solution

Check: 0.64: 0.11 = 6 approx Ok!

Bye from Italy,

C6H6

• HPV
Lv 7
9 years ago

If the ratio of acid to water is 6:1, then you have 7 total parts of solution. 1/7 of the solution is water, the rest acid.

4 gallons x 1/7 = 0.57 gallons water, the rest acid (3.43 gallons)

3 gallons x 1/7 = 0.43 gallons water, the rest acid (2.57 gallons)

3/4 gallons x 1/7 = 0.11 gallons water, the rest acid (0.64 gallons)