Anonymous
Anonymous asked in Science & MathematicsPhysics · 8 years ago

# The Earth has an electric field whose magnitude near Earth's surface is about 150 N/C.?

The Earth has an electric field whose magnitude near Earth's surface is about 150 N/C. The direction of the field is towards the center of the earth. Assume that this field is due to charges that are uniformly spread over the Earth's surface. What is the Earth's net charge? Suppose that there is a charged particle in the air near the surface of the Earth with a mass of 1.3x10^-15 kg the only forces acting on the particle are gravity and the electron force due to its charge. If this particle remains at rest find the sign and magnitude of this charge.

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• Anakin
Lv 6
8 years ago

Magnetic field strength:

F = q(v x B) = qvBsin(90) =qvB

mg = qvB

B = mg/qv

where

F is the force (in newtons)

E is the electric field (in volts per metre)

B is the magnetic field (in teslas)

q is the electric charge of the particle (in coulombs)

v is the instantaneous velocity