# Super hard math problems!! Cucumbers are on sale, so you buy 100 pounds of them at the local market for...?

1. Cucumbers are on sale, so you buy 100 pounds of them at the local market for your restaurant. Each cucumber is actually 96 percent water. A few days later, the cucumbers have dried out to the point that each is now 83 percent water. How much do all your cucumbers weigh at this time in pounds?

2. Consider the function f(x)=8e^(−5x+4.)

As a function of x, f^(−1)(x)= .

(You may assume that x is in an appropriate domain for this inverse function.)

In interval notation, the domain of f^(−1)(x) is...

3. Find the sum of all positive integers less than 3300 that are NOT divisible by 13.

4. Find all solutions to the equation −28sin^2(x)+43+41cos(x)=0 for 0<x<2pi. Give your answer as a comma-separated list in increasing order.

5. Find all solutions to the equation −7sin(2x)+5sin(x)=0 for 0x2. Give your answer as a comma-separated list in increasing order.

This is for some extra credit stuff i'm doing, could someone help me out?

Update:

you don't have to answer all them! anything you can do to help would be amazing :)

Relevance
• sepia
Lv 7
9 years ago

1).

Cucumbers are on sale, so you buy

100 pounds of them at the local market for your restaurant.

Each cucumber is actually 96 percent water.

A few days later, the cucumbers have dried out to the point that

each is now 83 percent water.

How much do all your cucumbers weigh at this time in pounds?

100*83/96 = 86.46 pounds

2).

Consider the function f(x) = 8e^(-5x + 4.)

As a function of x, f^(-1)(x) = .

(You may assume that x is in an appropriate domain for this inverse function.)

In interval notation, the domain of f^(-1)(x) is...

3).

Find the sum of all positive integers less than 3300 that are NOT divisible by 13.

4).

Find all solutions to the equation

-28sin^2(x) + 43 + 41cos(x) = 0 for 0<x<2pi.

5).

Find all solutions to the equation

-7sin(2x) + 5sin(x) = 0 for 0x2.

• Anonymous
9 years ago

weight of cucumber = 100 pounds

quantity of water inside = 96% = 96 pounds

so, quantity besides water = 4% = 4 pounds.

after few days

remaining quantity of water = 83%

quantity besides water = amount as before = 4 pounds

present weight = 83+4 = 87 pounds.

• Anonymous
9 years ago

You go to my school because I have the same math problems :P

Source(s): IMSA