Finding enthalpy given bond enthalpy values?

Given the following bond enthalpy values, calculate the enthalpy of formation for gas phase isopropanol, C3H7OH at 25 °C. BE (C–C) = 346 kJ mol–1 BE (C–H) = 4.00 × 102 kJ mol–1 BE (C–O) = 352 kJ mol–1 BE (O–H) = 465 kJ mol–1 BE (O=O) = 498 kJ mol–1 BE (H–H) = 432 kJ mol–1 The enthalpy of formation of C(g) is... show more Given the following bond enthalpy values, calculate the enthalpy of formation for gas phase isopropanol, C3H7OH at 25 °C.
BE (C–C) = 346 kJ mol–1
BE (C–H) = 4.00 × 102 kJ mol–1
BE (C–O) = 352 kJ mol–1 BE (O–H) = 465 kJ mol–1
BE (O=O) = 498 kJ mol–1 BE (H–H) = 432 kJ mol–1
The enthalpy of formation of C(g) is 715.0 kJ mol–1.
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