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# need help in math:( factorising.. please help!?

what is the answer to this..

factorise fully..

8p*little2*q + 12p

and also..

factorise fully..

20w*little2*y+ 24wy*little3*

please help!!

### 6 Answers

- IanLv 49 years agoFavorite Answer
I'm going to assume by "little2" you mean squared, which you would show like this: x^2 (Little2 is kinda cute though).

Anyways,

8(p^2)q + 12p Find the greatest common factor

4p(2pq + 3)

20(w^2)*y+ 24w(y^3) Find the greatest common factor

4wy(5w + 6y^2)

If you're having trouble finding the GCF (greatest common factor), don't worry, it's something you get faster at once you have done it a bunch.

If you can't do it mentally you can also break everything up into into prime numbers to find the GCF.

An example of this:

20(w^2)*y+ 24w(y^3)

2*2*5*w*w*y + 2*2*2*3*w*y*y*y

It's now easy to see that "2*2*w*y" is the GFC.

(2*2*w*y)(5*w + 2*3*y*y)

4wy(5w + 6y^2)

Voila!

- Mr PeuterschmitLv 79 years ago
Lol @ "little 2"; pronounce it "squared" - it means "p multiplied by p" :)

8p²q + 12p

We need to find what is "common" in both parts of this. There is a p in both parts, as well as a multiple of 4. So, we take these outside of our brackets.

4p (2pq + 3). If we expanded this now, we would get 8ppq + 12p, which would be 8p²q + 12p

So, number 2,

20w²y+24wy³

The "little 3" is pronounced "cubed", and simply means "p times p times p again".

So, we have a multiple of 4 in both parts again, as well as a w and a y

So, take these outside the bracket:

4wy(5w + 6y²). Again, if this were expanded, we'd get the original back. ^_^.

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