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# Radical Equation...Part 1?

Show that both sides of the radical equation are equal.

sqrt{7} - sqrt{8 - 2(sqrt{7}} = 1

### 3 Answers

- QCLv 79 years agoFavorite Answer
√7 − √(8 − 2√7)

= √7 − √(7 − 2√7 + 1)

= √7 − √((√7 − 1)(√7 − 1))

= √7 − √((√7 − 1)²)

= √7 − (√7 − 1)

= √7 − √7 + 1

= 1

Mαthmφm

- SueLv 79 years ago
√7 - √(8 -2√7) = 1 Get one root on each side of the equals.

- √(8-2√7) = (1 - √7)

[- √(8-2√7)]² = (1 - √7)² Square both sides, remember √n² = n and (A - B)² = A² - 2AB + B².

8 - 2√7 = 1 - 2√7 + 7 Collect like terms.

8 - 2√7 = 8 - 2√7

- lenhardtLv 44 years ago
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