If k = abc + 1, then prove that (k,a) = (k,b) = (k,c) = 1?
I have gotten this far, can anybody help me with the last few steps:
Suppose d divides k and d divides a, then k = du and a = dv
So du = k = abc + 1 = dvbc + 1
Therefore du = dvbc + 1......how do I show that d divides 1?
The parentheses imply greatest common divisor
- fizixxLv 78 years agoFavorite Answer
I'm afraid I don't understand the notation.
What do the quantities in parentheses represent? ---- (k,a), (k,b) & (k,c)