an object weighing 32 N on the Earth's surface?

would only weigh 2 N when its distance from the center of the Earth is

a. halved

b. tripled

c. quadrupled

d. doubled

i feel like its a trick question, but i cant seem to get the answer to this question.

Update:

THANK YOU!!!! =)))

2 Answers

Relevance
  • 8 years ago
    Best Answer

    2/32 is 1/16

    It's proportional to the distance squared, so a distance change of 4 would decrease the weight by 1/16. (c)

  • Ray
    Lv 7
    8 years ago

    This is an example of what is known as an inverse square law.

    If, for example, the distance is increased by a factor of 3 then the force will decrease by 3² = 9.

    Now, in your example, the force has decreased by a factor of 16. This means the distance has increased by √16 = 4, that is quadrupled.

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