# A random variable X has a probability distribution as follows:?

A random variable X has a probability distribution as follows:
X: 0 1 2 3_
P(X): 2k 3k 13k 2k
Then the probability that P(X < 2.0) is equal to
(a) 0.90.
(b) 0.25.
(c) 0.65.
(d) 0.15.
(e) 1.00.
How do you solve it?
Step by step please...
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A random variable X has a probability distribution as follows:

X: 0 1 2 3_

P(X): 2k 3k 13k 2k

Then the probability that P(X < 2.0) is equal to

(a) 0.90.

(b) 0.25.

(c) 0.65.

(d) 0.15.

(e) 1.00.

How do you solve it?

Step by step please...

X: 0 1 2 3_

P(X): 2k 3k 13k 2k

Then the probability that P(X < 2.0) is equal to

(a) 0.90.

(b) 0.25.

(c) 0.65.

(d) 0.15.

(e) 1.00.

How do you solve it?

Step by step please...

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