Anonymous
Anonymous asked in Science & MathematicsMathematics · 8 years ago

Let n and k be any positive integers with k less than or equal to n. Prove C(n,k)=C(n,n-k).?

2 Answers

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  • 8 years ago
    Best Answer

    C(n,n - k) =

    n!/((n - k)! (n - (n - k))!) =

    n!/((n - k)! (n - n + k)!) =

    n!/((n - k)! k!) =

    C(n,k)

  • ?
    Lv 6
    8 years ago

    C(n, k) = (n)! / [ (k)! (n -- k)! ] = (n)! / [ (n -- k)! (k)! ] = C(n, n -- k) QED

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