What is a line that is perpendicular to the equation 4x – 12y = 2 and passes through the point (10, –1)?
I have no idea how to do this and I have been trying very hard to understand by getting extra help and searching it on the internet. Please be very detailed and specific. Thank you very much in advance and have a nice night!
- JustoLv 79 years agoFavorite Answer
The slope of the line ax+by=c is m =-a/b and the slope the perpendiculars is m' = a/b. Thus the slope the perpendicular to the equation 4x – 12y = 2 is -12/4 =-3
And the equation of line that passes through (10, -1) and have a slope -3 is
y-(-1) = -3(x-10)
3x + y = 29