Find all real number solutions for the equation.?

a.) 3x^3 = 48x

b.) x^4 - 10,000 = 0

i have my answers but not 100% their right

any help would be appreciated.

3 Answers

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  • Anonymous
    9 years ago
    Favorite Answer

    a) 3x^3 = 48x

    divide thru by 3x to get

    x^2 = 16

    so x = 4 or -4

    b) x^4 - 10,000 = 0

    add 10,000 to both sides.

    10,000 is a perfect fourth power so

    x = 10 or -10

    Jim

    Source(s): BS Computer Science
  • 9 years ago

    The answers are:

    3x^3 (also means3.x.x.x) = 48x

    (3.x.x.x)/x = 48x/x (divided both sides by x)

    3x^2(or 3x.x) = 48

    (3x^2)/3 = 48/3 (3 divided by both sides)

    x^2 = 16(Square 16 because of x^2)

    x = 4

    x^4 - 10000 = 0 (Add 10000 in both sides)

    +10000 +10000

    x^4 = 10000

    x = 10

  • David
    Lv 7
    9 years ago

    3x^3 - 48x = 0

    3x(x^2 - 16) = 0

    3x(x + 4)(x - 4) = 0

    3x = 0

    x= 0

    x + 4 = 0

    x = -4

    x - 4 = 0

    x = 4

    x = {-4, 0, 4}

    x^4 - 10000 = 0

    (x^2 + 100)(x^2 - 100) = 0

    (x^2 + 100)(x + 10)(x - 10) = 0

    x^2 + 100 = 0

    x^2 = -100

    x = ± √-100

    x = ± 10i

    x + 10 = 0

    x = -10

    x - 10 = 0

    x = 10

    real number solutions

    x = {-10, 10}

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