Im studying for my test tomorrow on Polynomials, and the practice sheet gives me the polynomial with the points (1,0), (2,10), (3, 42), (4,108) (5, 220), (6, 390).

What is the equation? What is the equation in factored form? And how did you get it?

Relevance
• Substitute (1, 0).

a(1)^5 + b(1^4) + c(1^3)+d(1^2)+e(1)+f= 0

a +b + c+d+e+f = 0                  

Substitute (2, 10).

a(2)^5 + b(2)^4 + c(2)^3+d^(2)^2+e(2)+f = 10

32a+16b+8c+4d+2e+f=10                     

Substitute (3, 42).

a(3)^5 + b(3)^4 + c(3)^3+d^(3)^2+e(3)+f = 42

243a+81b+27c+9d+3e+f=42

Substitute (4, 108).

a(4)^5 + b(4)^4 + c(4)^3+d^(4)^2+e(4)+f =108

1024a+256b+64c+16d+4d+f=108

Substitute (5, 220).

a(5)^5 + b(5)^4 + c(5)^3+d^(5)^2+e(5)+f =220

3125a+625b+125c+25d+5e+f=220

Substitute (6, 390).

a(6)^5 + b(6)^4 + c(6)^3+d^(6)^2+e(6)+f =390

7776a+1296b+216c+36d+6e+f=390

using matrix you get

a=0

b=0

c=2

d=-1

e=-1

f=0

0(x)^5 + 0(x^4) + 2(x^3)+-1(x^2)+-1(x)+0= y

2x^3-x^2-x=y

x(x-1)(2x+1)=y

Source(s): PoPe
• Its frustrating to tell if the denominators are (t + 2), (t + a million), and (40-one - 2t). i'm guessing they are. substitute 20 for t interior the equations. a) A(20) = sixteen.36 b) B(20) = 27.27 c) C(20) = 50 So the college might would desire to be in section C.