Question about trigonometry and finding x?

I really have no clue how to do this and need help. It says solve for x in the given interval.

sec x=-2radical(3)/3, pi/2 < x < pi.

The next one says csc x = 2, 0 < x < pi/2

Can someone please explain one or both of these??

* all < are greater than or equal to.

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  • 9 years ago
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    sec x=-2radical(3)/3, pi/2 < x < pi.

    cosx = - 3/(2√3)..............[ -3/(2√3) ]*(√3/√3) ...............- √3/2

    cosx = - √3/2

    x= cos^(-1) -√3/2

    x = Reference Angle of pi/6.................But in Quad II,

    x= 5pi/6............ANSWER

    csc x = 2, 0 < x < pi/2

    sin x = 1/2

    x = sin^(-1) 1/2

    x = pi/6 ............ANSWER

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