Anonymous
Anonymous asked in Science & MathematicsMathematics · 9 years ago

find the product 10 points! x(3x-1)?

x(3x-1)

(x+1) (x^2+x-1)

(5x-4) (3x-1)

6 Answers

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  • Anonymous
    9 years ago
    Favorite Answer

    Multiply each term by x to get...

    x(3x - 1)

    = x * 3x - x

    = 3x² - x

    I hope this helps!

    Source(s): Σ
  • Anonymous
    9 years ago

    X=3

  • 9 years ago

    x (3x - 1) ---------Distribute the x to the 3x and -1.

    3x^2 - x

    (x+1) (x^2+x-1) ---Distribute the x to each term in (x^2+x-1). Then distribute/multiply 1 by (x^2+x-1).

    x^3 + x^2 - x + x^2 + x - 1 -------simplify

    x^3 + x^2 + x^2 - 1

    (5x-4) (3x-1) ------Do the FOIL method. First, Outer, Inner, Last. Multiply the first term in each pair of parentheses (5x * 3x). Then the outer terms: 5x and -1. Then the inner terms, -4 and 3x. And finally the last terms, -4 and -1. Then add all those products together.

    15x^2 + (-5x) + (-12x) + (4)

    15x^2 - 5x -12x + 4 -------Combine like terms.

    15x^2 - 17x + 4

  • 9 years ago

    For the first one, you multiply x throughout the quantity in the parentheses. It will look like this:

    x(3x-1) = 3x^2 - x

    This is like the first one, just multiply both x and +1 to the quantity and add them together.

    (x)(x^2+x-1) = x^3 + x^2 - x

    (+1)(x^2+x-1) = +x^2 + x - 1

    Combine like terms: x^3 + x^2 - x + x^2 + x - 1

    = x^3 + 2x^2 - 1 (the -x and +x cancel out)

    This is a FOIL problem

    First: 15x^2

    Outer: -5x

    Inner: -12x

    Last: +4

    Combine like terms: 15x^2 - 17x + 4

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  • Anonymous
    9 years ago

    The product is simply the answer you get when you multiply things together.

    x(3x-1) distribute the x to get 3x^2-x

    (x+1) (x^2+x+1) multiply the x times (x^2+x+1) and ad that to 1 times (x^2+x+1) to get:

    x^3+x^2+x + x^2+x+1 and simplify to get x^3+2x^2+2x+1

    (5x-4) (3x-1) use the FOIL method. FOIL stands for first, outer, inner, last and means multiply the first term in each binomial, then the outer term in each binomial, then the inner term in each binomial, then the last term in each binomial and ad them together.

  • 9 years ago

    x(3x - 1)

    3x² - x

    ¯¯¯¯¯¯

    (x + 1)(x² + x - 1)

    (x³ + x² - x) + (x² + x - 1)

    x³ + x² + x² - x + x - 1

    x³ + 2x² - 1

    ¯¯¯¯¯¯¯¯¯¯

    (5x - 4)(3x - 1)

    15x² - 5x - 12x + 4

    15x² - 17x + 4

    ¯¯¯¯¯¯¯¯¯¯¯¯

    Source(s): 12/11/11
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