Calculus math problem help? Evaluate?

Find the area represented by the definite integral.

∫^1,0 6 x dx/ SQ(16 + 3x2)

please provide steps so I know how to do it

2 Answers

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  • Amy
    Lv 7
    8 years ago
    Best Answer

    Let u = 16 + 3x^2

    du/dx = 6x

    6x dx / sqrt(16 + 3x2) = du / sqrt(u) = u^(-1/2) du

    Translate the limits from x = 0 and x = 1 to u = 16 + 3(0^2) and u = 16 + 3(1^2)

    19

    ∫ u^(-1/2) du

    16

  • 8 years ago

    ∫^1,0 6 x dx/ SQ(16 + 3x2)

    Before I/we consider your question it seems critical to detail what your integration limits are -- lower limit 1, upper limit 6??

    The integrand seems like it might be a square root in the denominator: √ (16 + 3x²) ??

    Please clarify and provide more detail.

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