# Calculus math problem help? Evaluate?

Find the area represented by the definite integral.

∫^1,0 6 x dx/ SQ(16 + 3x2)

please provide steps so I know how to do it

### 2 Answers

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- AmyLv 78 years agoBest Answer
Let u = 16 + 3x^2

du/dx = 6x

6x dx / sqrt(16 + 3x2) = du / sqrt(u) = u^(-1/2) du

Translate the limits from x = 0 and x = 1 to u = 16 + 3(0^2) and u = 16 + 3(1^2)

19

∫ u^(-1/2) du

16

- answerINGLv 68 years ago
∫^1,0 6 x dx/ SQ(16 + 3x2)

Before I/we consider your question it seems critical to detail what your integration limits are -- lower limit 1, upper limit 6??

The integrand seems like it might be a square root in the denominator: √ (16 + 3x²) ??

Please clarify and provide more detail.

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