how do I get from [1/((1/(80+j80))+(1/(20e^(-j90)))] to 22.6e^(-j81.9)?
This is a complex numbers problem for a circuits class.
- GRAHAMLv 68 years agoFavorite Answer
Put the LHS all in cartesian form and collect common terms, then convert to polar form.
First part of LHS requires multiplying top and bottom by the conjugate of the bottom i.e. (80-j80).
This remove the j term from the denominator.
Second part of LHS is converted using Re^(jθ)=Rcosθ+jRsinθ.
- 8 years ago