# I have a statistics question?

The weight of steers in a herd are distributed normally the variance is 40,000 and the mean steer weight is 1500 LBS. find the probability that a randomly selected steer weighs more then 1,900 LBS. Explanation would be great but answer works too lol i lost my notes

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- Anonymous9 years agoFavorite Answer
P(X > 1900)

= P(Z > (1900 - 1500) / 200)

= P(Z > 2)

= 1- Φ(2)

= 1 - 0.97725

= 0.02275

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- Anonymous9 years ago
Ans:

mean=1500

sd=sqrt(40,000)

test statistic, z= (x- mean )/sd

Need to find P(x>1900)=?

if x=1900 , then z=(1900-1500)/sqrt(40,000)=2

P(x>1900)=P(z>2)=0.5-P(0<z<2)

=0.5-0.4772

=0.0228(Ans.)

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