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# solve 2cos(2x) + 4 sinx cosx = √(2) between the limits 0 ≤x ≤2π?

i am just sooooooooooooo confused lol

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- 8 years agoFavorite Answer
Simplify LHS to: 2{cos(2x)+sin(2x)}

= 2√2{(1/√2)cos(2x)+(1/√2)sin(2x)}

=2√2(cos(2x-(π/4)))

Solve.

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