help with math help please?

There were 56 runners to start a race. In the first half of the race, 1/4 of them dropped out. In the second half of the race, 3/7 of the remaining runners dropped out. How many runners finished the race?

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  • Anonymous
    9 years ago

    First half 1/4 th means 14 left the race. remaining 42 out of which 3/7 th means 18 left the race. now only 24 left they finished the race

    ie 1/4 * = 14

    3/7 * 49 = 18

    last 24

  • Anonymous
    9 years ago

    1/4 of 56= 14

    56-14=42

    3/7 of 42= 18

    42-18= 24

    24 runners finished the race

    EDIT----

    Damn, some people really suck at maths or don't read questions properly.

    "Tany" The question says "1/4 of them dropped out." it doesn't say that 1/4 of them stayed in the race so your calculations are not correct. The only correct answers so far are roxa's and mine.

  • 9 years ago

    The answer is 24.

    56 (1/4) = 14 (dropped out)

    56-14 = 42 left in first half.

    42 (3/7) = 18 (dropped out)

    42 - 18 = 24 left in the race.

  • 9 years ago

    1/4 of 56 is 14

    56-14=42

    3/7 of 42 is 18

    14+18=32, therefore, 32 people dropped out.

    56-32= 24, therefore, 24 people finished the race.

    Sorry for the mistake i made earlier, i misread the question

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  • 9 years ago

    24 runners finished the

    race.

  • 9 years ago

    56 X 1/4 = 14

    56 -14 = 42

    3/7x42 = 18

    42 -18 = 24 ANSWER

  • 9 years ago

    56%4= 14... 56-14= 42... 3%7= .428 x 42 = 18.... 42-18= 24....... 24 finished race

  • 18 Runners finished the game.

  • 9 years ago

    The answer is 6

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