Solve 4[x-(3-2x)]+5=3(x+11)?

Please help! Solve 4[x-(3-2x)]+5=3(x+11)

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  • David
    Lv 7
    9 years ago
    Favorite Answer

    4[x - (3 - 2x)] + 5 = 3(x + 11)

    4[x - 3 + 2x] + 5 = 3x + 33

    4[3x - 3] = 3x + 28

    12x - 12 = 3x + 28

    9x = 40

    x = 40/9

  • Taylor
    Lv 5
    9 years ago

    The first thing you want to do is get rid of all the brackets.

    4[x -(3-2x)]+5 = 3(x+11)

    4[x-3+2x]+5 = 3x + 33

    4x-12+8x+5 = 3x+33

    4x+8x-3x = 33-5+12

    9x = 40

    Then divide both sides by 9 to solve for x.

  • 9 years ago

    x=40/9

  • Anonymous
    9 years ago

    4[-3 - x] + 5 = 3x + 33

    -12 - 4x + 5 = 3x + 33

    Now, we combine the like terms!

    -7 = 7x + 33

    -40 = 7x

    x = -5.71

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  • 9 years ago

    4[x-(3-2x)]+5=3x+33

    4[x-3+2x]+5=3x+33

    4[3x-3]+5=3x+33

    12x-12+5=3x+33

    12x-7=3x+33

    9x=40

    x=40/9

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