# The Hubble Space Telescope orbits Earth 614 km above Earth's surface. ....?

The Hubble Space Telescope orbits Earth 614 km above Earth's surface. What is the period of the telescope's orbit?

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• Anonymous
8 years ago

G . M . m / R^2 = m . v^2 / R

v = 2πR / T

G . M / R^2 = 4π^2 R / T^2

T^2 = 4 π^2 R^3 / G . M

T = 2π . √ R^3 / G . M = 2π .√ ( 6.984 . 10^6)^3 / 6.67 . 10^–11 . 5.98 . 10^24

T = 6.28 √10^5 . 8.54 = 5803 s ( 96.7 minutes )

Source(s): Old teacher
• Any merchandise in low earth orbit could have an orbital era of approximately ninety minutes. For a extra appropriate fee, you will could desire to apply the same old gravitational consistent, the mass of the earth, and the radius of the orbit as taken from the earth's middle. on the different hand, use the gravitational acceleration on the earth's floor, calculate the help in that because of the orbit's distance above the exterior, and use that tension to stability the centrifugal tension bobbing up from the satellite tv for pc's inertia. The latter computation would be extra straightforward because of the fact it avoids coping with extensive numbers.