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# new york me44 math problems

1.which of the following is the sum of the solutions of 4x^2-35x-9=0?

(F)-8

(G)8

(H)8.75

(J)9.25

solve this question by factoring

1. w^2-8w=0

please answer as soon as possible cos i have to hand this hw to my teacher tomorrow!!!

can you explain in more details?

like the process, step by step

MY MATH IS TERRIBLE!

THANKS A LOT!!

### 2 Answers

- 10 years agoFavorite Answer
1.Factorize 4x^2-35x-9 first.

Let 4x^2-35x-9 be (4x+a)(x+b).

Then, split -9 into two numbers which only can be 1,9 or 3,3.(ignore negative signs first)

Let us try1,9 first.

The answer will be(4x+1)(x-9).

Either 4x+1 or x+9 equals to 0.

If 4x+1=0, x equals to -1/4.

If x-9=0, x equals to 9.

9+(-1/4)=8 3/4.

2.w^2-8w=0

Take away the common factor, it becomes to w(w-8)=0

so either w=0 or w-8=0

If w=0, w=0.

If w-8=0,w=8

So,w can be 0 or 8.

- williamLv 510 years ago
4x^2-35x-9=0

(4x+1)(x-9)=0

x = -1/4 (-0.25) or x = 9

their sum is : -0.25 + 9 = 8.75

+++

w^2 - 8w = 0

w(w - 8) = 0

w = 0 or w = 8