How to evaluate a function with a variable in the domain?
The problem is 2/((3x)*2)
i got a = .8165 is this right? how do I get the variable out of the denominator?
- DragonLv 69 years agoFavorite Answer
The referenced source describes "domain" as the x-values used to determine the curve for f(x) or the y-values (know as the "range")
The curve for the stated problem (2/(3x)^2) is continuous for all values of "X" except zero so the domain can be written "X equal all real values except zero"
- daakLv 44 years ago
a million) g(x) = sqrt(x) g(f(x)) = sqrt(x+2) sqrt(x+2) is defined such that x>=-2 for the reason that sqrt of a detrimental huge sort is undefined hence the area is all genuine nos such x>=2 2. assume f(x)= -4x+3 and g(x)= a million/x+2 evaluate f(g(x)) and g(f(x)) for x. be conscious any regulations. f(x) = -4x + 3 f(g(x)) = -4(a million/x + 2) + 3 the area is all genuine nos such that x isn't equivalent to 0 g(x) = a million/x + 2 g(f(x)) = a million/(-4x +3) + 2 -4x + 3 should not be 0 or -4x + 3 <> 0 -4x <> -3 x<>3/4 the area is all genuine nos such that x isn't equivalent to 3/4