# Area of rectangle question?

I have a problem where its a rectangle and it shows a fraction of 7/3x as its height ad 4x as its width. BUT x=6. I'm not sure when I'm solving this problem I'm doing multiplication first like 7/3 times 6 and 4 times 6, and then figuring out length x width?

Relevance
• Anonymous
9 years ago

Yes, you are doing it correctly. Think of it like this (7/3*x)(4*x). In other words, (7/3*6)(4*6)

• Length/Height = 7/3x; Breadth/Width = 4x

Area of rectangle = length X width

= 7/3x X 4x

x = 6

Therefore = 7/3 (6) X 4 (6)

= 14 X 24

= 336

Width is 4*6 = 24

• It doesn't matter. Multiplication and division is commutative. That is, it doesn't matter what order you multiply or divide.

Area of a rectangle is l*w. That is, (7x/3)*(4x), where x = 6. Note you wrote it wrong. 7/3x is not the same thing as (7/3)x. Be careful of this.

Anyways, there's no difference between going (7*6/3)*(4*6) and going (7/3)*6 *(4/6). You get the same answer both ways.

• 7/3 * 6 = 14

4 * 6 = 24

14 * 24 = 336

Yes you're correct.