Area of rectangle question?

I have a problem where its a rectangle and it shows a fraction of 7/3x as its height ad 4x as its width. BUT x=6. I'm not sure when I'm solving this problem I'm doing multiplication first like 7/3 times 6 and 4 times 6, and then figuring out length x width?

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  • Anonymous
    9 years ago
    Favorite Answer

    Yes, you are doing it correctly. Think of it like this (7/3*x)(4*x). In other words, (7/3*6)(4*6)

  • 9 years ago

    Length/Height = 7/3x; Breadth/Width = 4x

    Area of rectangle = length X width

    = 7/3x X 4x

    x = 6

    Therefore = 7/3 (6) X 4 (6)

    = 14 X 24

    = 336

    Width is 4*6 = 24

  • JBere
    Lv 6
    9 years ago

    It doesn't matter. Multiplication and division is commutative. That is, it doesn't matter what order you multiply or divide.

    Area of a rectangle is l*w. That is, (7x/3)*(4x), where x = 6. Note you wrote it wrong. 7/3x is not the same thing as (7/3)x. Be careful of this.

    Anyways, there's no difference between going (7*6/3)*(4*6) and going (7/3)*6 *(4/6). You get the same answer both ways.

  • 7/3 * 6 = 14

    4 * 6 = 24

    14 * 24 = 336

    Yes you're correct.

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  • DWRead
    Lv 7
    9 years ago

    Every operation is multiplication, which is commutative, so it doesn't matter what gets multiplied first.

    h = 7x/3

    w = 4x

    area = hw = 28x²/3 = 336 units²

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