Anonymous
Anonymous asked in Science & MathematicsPhysics · 9 years ago

# Confusing Physics Problem?

An object is released from rest on a planet that has no atmosphere. The object falls freely for 5.51 m in the first second.

What is the magnitude of the acceleration due to gravity on the planet?

I thought it would be 5.51 m/s2, but apparently that's wrong. Does anyone know why and how to get the real answer?

Relevance
• 9 years ago

Look up the kinematic equations.

Find the one that has what you want to find and what you know.

In this case, it's "h = s + ut + at^2/2"

where h = distance travelled (=5.51metres), s = starting distance (=0), u = starting velocity (=0), a = acceleration (what you want to find) and t = time elapsed (=1 second)

So:

5.51 = 0 + 0 + a/2

a = 11.02 ((metres per second)/second)) or m/s^2

(The other guy didn't do the doubling right, but shows the same method)

• Anonymous
9 years ago

s=5.51 u=0 a=a t=1

Use the equation s=ut+.5at^2

5.51=0t+.5a(1)^2

5.51=.5a

a=10.02 ms^-2