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# I need help with this math problem involving polynomial roots! :?

Given the polynomial equation and the one root, find the remaining roots.

6X^3 + 11X^2 - 4X - 4 = 0 ; root = -2

Thank you so much in advance!

### 2 Answers

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- I'm with StupidLv 79 years agoFavorite Answer
start with synthetic division:

___________

-2 ) 6 11 -4 -4

0 -12 2 4

——————

6 -1 -2 0

so

(6x³ + 11x² - 4x - 4) / (x + 2) = 6x² - x - 2

then

6x² - x - 2 =

(3x - 2)(2x + 1)

so

remaining roots are:

x = 2/3 and x = -1/2

♣♦

- Anonymous4 years ago
If a polynomial with rational coef. has the complicated root a+bi it additionally ought to have the cojugate a -bi.So your polinom must be a minimum of (x-2)(x+3)(x+3i)(x-3i) = (x-2)(x+3)(x^2+9) which complies

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