Calculate the pH of a Solution?
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Calculate the ph of the solution made by adding 0.50 mol of propanoic acid (C2H5COOH or HC3O5H2) and 0.30 mol of sodium propanoate (C2H5COONa or NaC3H5CO2) to 1.00 L of water. The ...show more
Equilibrium concentrations will be essentially the same as initial concentrations, so ka=base/acid comes to 1.3*10^-5=x.30/.50 or simplified, 1.3*10^-5=.60x. Divide both sides by .60 to isolate x, you get 2.17*10^-5. If you look at your ICE chart, H3O=x, so -log(2.17*10^-5)=4.66
Reading my Chem textbook.
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