What is the velocity of the boat after Batman lands in it?
Batman (mass = 91kg) jumps straight down from a bridge into a boat (mass=150kg) in which a criminal is fleeing. The velocity of the boat is initially +11 m/s. What is the velocity of the boat after Batman lands in it?
- TBTLv 79 years agoFavorite Answer
conservation of momentum in the direction of the boat,
150 * 11 + 90 * 0 = (150 + 91) * v
v = 6.85 m/s
the velocity of the boat after Batman lands in it
answerSource(s): my brain (Prof TBT)
- 9 years ago
The intent of the question is to demonstrated conservation of linear momentum, though the example is pretty bad.
Assuming everything is ideal, the boat pretty much instantly increases in mass. Before batman jumps on, it has a linear momentum in the forward direction of
p = mv = (150)(11) = 1650 kg m / s
After batman jumps on, because he exerts no force in the forward or backward direction, linear momentum in that direction must be conserved. That is, it must be the same as before
p = 1650 kg m / s = m' v'
Where m' and v' are the mass and speed, respectively, of the boat after batman jumps on. We know the mass of batman and the boat, just compute the speed v'.
p = 1650 kg m / s = (150+91) v'
v' = 6.85 m/s
- billrussell42Lv 79 years ago
Conservation of momentum
initial momentum of boat is 150 x 11
momentum of bat is zero
final mass is 150+91 = 241
241v = 150*11
v = 6.85 m/s
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- suzetteLv 43 years ago
thanks to each and everyone of you guys for the answers!