Chelo asked in Science & MathematicsPhysics · 10 years ago

A little help with physics?

A skier is on a ramp, the ramp has an angle of 15º over the horizontal, the landing ramp is 50º below the horizontal.

If the speed of the skier is thet of 10m/s, whats the distance between the end of the ramp and the landing spot?

1 Answer

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  • Quark
    Lv 6
    10 years ago
    Favorite Answer

    x = 10 cos 65 * t + 1/2 ( 9.8 * sin 50) * t^2 -----> α = 15 + 50 = 65

    y = 10 sin 65 * t - 1/2 ( 9.8 * cos 50) * t^2

    y = 0 at the landing ramp

    0 = 10 sin 65 * t - 1/2 ( 9.8 * cos 50) * t^2

    0 = 7.66* t - 3.15 * t^2 --> t =7.66/3.15 = 2.43 s

    substitute t into x

    x = R = 10 cos 65 * 2.43 + 1/2 ( 9.8 * sin 50) * 2.43^2

    = 32.43 m

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