A little help with physics?

Question

A skier is on a ramp, the ramp has an angle of 15º over the horizontal, the landing ramp is 50º below the horizontal.

If the speed of the skier is thet of 10m/s, whats the distance between the end of the ramp and the landing spot?

Answer 1

Favorite Answer

x = 10 cos 65 * t + 1/2 ( 9.8 * sin 50) * t^2 -----> α = 15 + 50 = 65

y = 10 sin 65 * t - 1/2 ( 9.8 * cos 50) * t^2

y = 0 at the landing ramp

0 = 10 sin 65 * t - 1/2 ( 9.8 * cos 50) * t^2

0 = 7.66* t - 3.15 * t^2 --> t =7.66/3.15 = 2.43 s

substitute t into x

x = R = 10 cos 65 * 2.43 + 1/2 ( 9.8 * sin 50) * 2.43^2

= 32.43 m