From street level, superman spots Lois Lane in trouble as theevil villain, Lex Luthor, drops her from near the?

From street level, superman spots Lois Lane in trouble as theevil villain, Lex Luthor, drops her from near the top of the EmpireState Building. At that very instant, the Man of Steel startsupward at a constant acceleration to attempt a midair rescue ofLois. Assuming she was dropped at a height of 300 m and thatsuperman can accelerate straight upward at 15 m/s2,determine how far lois falls before he catches her.

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  • Tim G
    Lv 4
    9 years ago
    Favorite Answer

    Lois Lane's distance from the top:

    d = d0 + (1/2)at²

    d = (1/2)gt²

    d = (1/2)(9.8)t²

    = 4.9t² Equation A

    As expected, Lois Lane's distance from the top grows with time.

    Superman's distance from the top:

    d = d0 + (1/2)at²

    d = 300 -(1/2)(15)t²

    = 300 -7.5t² Equation B

    As expected, Superman's distance from the top shrinks with time.

    Set Equation A equal to Equation B and solve for t²

    4.9t² = 300 -7.5t²

    12.4t² = 300

    t² = 300 / 12.4

    t² = 24.19

    Substitute t² = 24.19 into either Equation A or Equation B for your final answer:

    From Equation A:

    d = 4.9(24.19) = 119m

    Verify your answer by substituting into Equation B:

    d = 300 -7.5(24.19) = 119m

    So the answer is definitely 119 meters

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  • 3 years ago

    Superman Height

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  • God
    Lv 7
    9 years ago

    Lois and superman will move according to:

    y_l=h0+v0t+g*t^2/2 ; v0=0

    y_s=v0*t+a*t^2/2 ; v0=0

    when they meet:

    y_l=y_s => h0+g*t^2/2 = a*t^2/2

    300-9.8*t^2/2 = 15*t^2/2

    600-9.8*t^2 = 15*t^2

    solve, t=~4.92s

    y_s = 15*4.92^2/2 = 181.55m - the height at which they meet

    Therefore the fall is 300-181.5=118.45m

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  • Anonymous
    9 years ago

    He doesn't... Batman swings by and saves her!

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