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Anonymous
Anonymous asked in Science & MathematicsMathematics · 9 years ago

Prove the following identity algrebraically: 1-(sinx)(cosx)(tanx)= (cos^2)x?

Prove the following identity algrebraically: 1-(sinx)(cosx)(tanx)= (cos^2)x

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  • Anonymous
    9 years ago
    Favorite Answer

    substitute

    tanx=sinx/cosx and

    1-sin^2 x = cos^2 x

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  • 9 years ago

    LHS

    = 1-(sinx)(cosx)(tanx)

    = 1 - sinx * cos x * sin x / cos x

    = 1- sin^2 x

    = cos^2 x

    = RHS

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  • 4 years ago

    convey tanx =sin x/cos x , and look on the id for sin 2x (or cos 2x. convey, you'll see which one to apply!) i need to handbook you to the answer, not provide it to you. that is extra effective!

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  • TC
    Lv 7
    9 years ago

    1 -( sin)(cos)(tan) = cos^2

    1 - (sin)(cos)(sin/cos) = cos^2

    1 - (sin)(sin) = cos^2

    1 - sin^2 = cos^2

    cos^2 = cos^2

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