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# find a. given that y = k / (ax +2) and that y = 10 when x = 5 and y = 3.75 when x = 14?

Update:

Could you show step wise working out of the problem?

### 4 Answers

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- icemanLv 79 years agoFavorite Answer
k/(5a + 2) = 10

k/(14a + 2) = 3.75

k = 10 (5a + 2)

k = 3.75 (14a + 2)

50a + 20 = 52.5 + 7.5

2.5a = 12.5

a = 5

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- Imrul AhsanLv 69 years ago
y = k / (ax +2).....................(1)

Putting y=10 and x=5 in equation (1)---->

10 =k / (a*5 +2)

10 =k / (5a +2)

5a+2= k/10

50a+20=k--------------(2)

Again putting y=3.75 and x=14 in equation (1)------->

3.75 =k / (a*14 +2)

3.75 =k / (14a +2)

14a+2 =k/ 3.75

14*3.75 a+ 2*3.75 = k

52.5 a+7.5 = k -----------(3)

From equations (2) and (3),

50a+20 = 52.5 a+ 7.5

2.5 a = 12.5

a = 12.5/2.5 = 5

So a= 5

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- u.n. oLv 59 years ago
y(ax+2) = k

10(5a+2) = k

3.75(14a+2) = k

2.5a = 12.5

a = 5

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- 9 years ago
put the values and get the two equations in a and k.

answer should be a=5

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