A 11 pF capacitor is connected across a 63 V source. What charge is stored on it?

Answer in units of C.

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  • Anonymous
    9 years ago
    Best Answer

    .Q.A 11 pF capacitor is connected across a 63 V source. What charge is stored on it?

    Ans : Capacitance (C) = 11 pF = 11 * 10^(-12) F

    Potential (V) = 63 V

    Apply : Charge(Q) = CV

    => Q = {11 * 10^(-12)} * 63

    => Q = 693 * 10^(-12) C

    I wish you will appreciate my answer.

  • 3 years ago

    10 Pf Capacitor

  • 9 years ago

    Nobody has said Q=CV which is the formula you should be using. 11*(10^12)*63 (C)oulombs. Also the 11pF capacitor should have a working voltage above 63V so it doesn't vaporize when 63V is applied.

  • Anonymous
    9 years ago

    C = Q/V where V is the voltage across it, Q is the charge, and C is the capacitance

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  • 9 years ago

    C=q/v

    c=capacitance

    q=charge

    v=voltage

    therefore:-). The answer is 0.000000000693:-):-):-):-).

  • JOS J
    Lv 7
    9 years ago

    6.93*10^-10

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