# A 11 pF capacitor is connected across a 63 V source. What charge is stored on it?

Answer in units of C.

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- Anonymous9 years agoBest Answer
.Q.A 11 pF capacitor is connected across a 63 V source. What charge is stored on it?

Ans : Capacitance (C) = 11 pF = 11 * 10^(-12) F

Potential (V) = 63 V

Apply : Charge(Q) = CV

=> Q = {11 * 10^(-12)} * 63

=> Q = 693 * 10^(-12) C

I wish you will appreciate my answer.

- GibsonEssGeeLv 79 years ago
Nobody has said Q=CV which is the formula you should be using. 11*(10^12)*63 (C)oulombs. Also the 11pF capacitor should have a working voltage above 63V so it doesn't vaporize when 63V is applied.

- Anonymous9 years ago
C = Q/V where V is the voltage across it, Q is the charge, and C is the capacitance

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- 9 years ago
C=q/v

c=capacitance

q=charge

v=voltage

therefore:-). The answer is 0.000000000693:-):-):-):-).

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