# Probability question? *SAT?

I tried doing this, but I couldn't get the right answer.

Tiles numbered 1 to 1000 (inclusive) are placed in a bag. If a tile is chosen at random, what is he probability that the tile's number is even and a multiple of 5?

A- 1/10

B- 21/100

C- 3/10

D- 1/2

E- 141/200

Thank you so much!

Relevance

A- 1/10. 5 goes into 100, 20 times. Multiply this by 10 and get 200. Now since every other multiple of 5 is an even number, you have to divide 200 by 2 to get 100. This can be displayed as 100/1000. This can be reduced down to 10/100 to 1/10, which is the answer.

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• I am not sure about the equation that would give you the answer but i will try to explain my logic

first lets find the number of of numbers that are a mulitple of 5 between 1 and 100, ther are 20, so lets assume there will be 200 between 1 and 1000

of the 20 numbers between 1 & 100 only 10 are even ( 10,20,20,40,50,60,70,80,90,100) again lets assume then that there are 100 numbers between 1 and 1000 that are multiples of 5 and are even

so the probablity is 100/1000 or 1/10 That is assuming I have made all my assumptions correctly

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• Anonymous
9 years ago

i think you divide 1000 by 5: 1000/5=200 and divide this by 2: 200/2=100

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