Alpha Particle in Magnetic Field Physics please help?
An alpha particle (the nucleus of a helium atom formed by 2 protons and 2 neutrons with charge q = +2(1.6 x 10-19 C ) is moving perpendicular to a magnetic field of 0.680 tesla at a velocity of 2.90E+6 m/s ; calculate the magnitude of the magnetic force exerted on it.
Calculate the acceleration of the alpha particle.
What will be the radius of curvature of the path followed by the alpha particle in the magnetic field?
What would be the force on the alpha particle if it were traveling parallel to the magnetic field lines?
Any help would be great. Thanks!
- 9 years agoFavorite Answer
So the force on your particle will be v x B, which in your case will just be v*B because sin 90 is 1. So that is your force pointing to the center of the radius of your circular path, using the equation (mv^2)/r, you can find r because the sum of your radial forces is that force from before, v*B. You need to know the mass of your particle though.Source(s): My brain