How much time does it take a bullet to go 50ft at 500ft/sec?
- enginerdLv 610 years agoFavorite Answer
since s is 500 ft/sec in this case, and d is 50 ft, we get
500 ft/sec = 50 ft/ t
lets solve for t
start by multiplying each side by "t" in order to get it out of the denominator
500 ft/sec * t = 50 ft * t/t
t/t = 1
50 * 1 = 50
500 t feet/sec = 60 ft
divide both sides by 500 ft/sec and get
500 t feet/sec / (500 ft/sec) =50 ft / (500 ft/sec)
500 feet/sec divided by 500 ft/sec equals 1, and 1 times t is just t so
t=50 ft / (500 ft/sec)
t= .1 sec
so we went through that the way that uses the formula and works every time
but a quick look can give this a "makes sense" check
if you can go 500 feet in one sec, then it only going to take a tenth as long to go a tenth as far
so, 500 feet per 1 sec, means 50 feet in a tenth as long, or .1 sec
makes sense, huh?
- 10 years ago
- Anonymous10 years ago
500/1 = 50/0.1
Kind of like simplifying fractions.