Anonymous
Anonymous asked in Science & MathematicsMathematics · 9 years ago

Solve for A1/A2 in terms of R (logs)?

R = 2.3log(A1 + 3000) - 5.1

R = 2.3log(A2 + 34,000) - 7.5

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  • 9 years ago
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    R = 2.3log(A1 + 3000) - 5.1

    gives

    (R+5.1) = 2.3log(A1 + 3000)

    log(A1 + 3000) = (R+5.1)/2.3

    (A1 + 3000) = 10^[(R+5.1)/2.3]

    A1 = 10^[(R+5.1)/2.3] - 3000

    similarly

    A2 = 10^[(R+7.5)/2.3] - 34000

    Hope that helps.

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