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# The amplitude and period of a puck traveling 5.4m/s that slides into a spring with a constant of 15N/m?

A puck with mass m = 0.18 kg slides along a frictionless horizontal surface at v = 5.4 m/s. It hits and sticks to the free end of a spring with k = 15 N/m

What is its Amplitude, and Period.

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- BrambleLv 79 years agoFavorite Answer
The period = T = 2π√(m/k)

The motion is described by :

deflection = s = A.sin(ωt) where ω = √(k/m), A = amplitude and t = time. The velocity is:

v = ds/dt = A.ω.cos(ωt) so A.ω = A.√(k/m) = 5.4 at t=0, giving:

Amplitude = A = 5.4 x √(m/k) = 5.4.T/(2π)

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