The amplitude and period of a puck traveling 5.4m/s that slides into a spring with a constant of 15N/m?
A puck with mass m = 0.18 kg slides along a frictionless horizontal surface at v = 5.4 m/s. It hits and sticks to the free end of a spring with k = 15 N/m
What is its Amplitude, and Period.
- BrambleLv 79 years agoFavorite Answer
The period = T = 2π√(m/k)
The motion is described by :
deflection = s = A.sin(ωt) where ω = √(k/m), A = amplitude and t = time. The velocity is:
v = ds/dt = A.ω.cos(ωt) so A.ω = A.√(k/m) = 5.4 at t=0, giving:
Amplitude = A = 5.4 x √(m/k) = 5.4.T/(2π)