How to calculate bond enthalpy? please help?

Calculate the bond enthalpy of the N—H bond in NH3 using the data given below. Show your method of working clearly.

N2(g) + 3H2(g) ---------------> 2NH3
ΔHfθ = -92kJmol-1

Bond = N-N
Bond enthalpy/kJmol-1 = 946

Bond = H-H
Bond enthalpy/kJmol-1 = 436

thanks in advance!!! :)
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