find antiderivative u/(16+u^2)?

ln(16+u^2) ?

3 Answers

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  • Ed I
    Lv 7
    9 years ago
    Best Answer

    ∫ u du/(16 + u^2)

    Let w = 16 + u^2

    then dw = 2u du

    so (1/2) dw = u du

    We now have (1/2) ∫ dw/w = (1/2) ln w = (1/2) ln (16 + u^2) + C

  • satszn
    Lv 6
    9 years ago

    (1/2 ) ln(16+u^2)

  • 9 years ago

    1/2ln(16+u^2)+C

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