The square plates of a 2000-pF capacitor measure 20 mm by 20 mm and are separated by a dielectric that is 0.27?
The square plates of a 2000-pF capacitor measure 20 mm by 20 mm and are separated by a
dielectric that is 0.27 mm thick. The voltage rating of the capacitor is 500 V. The dielectric
constant of the dielectric is closest to:
A) 110 B) 150 C) 170 D) 140 E) 120
- 9 years agoBest Answer
Given parameters of capacitor are:
Capacitance C = 2000pF = 2000 x 10-12pF (1pF = 10-12F)
Separation of plates = thickness of dielectric = 0.27mm = 27 x 10-5m
Plates are square with dimension 20mm x 20mm
Hence area of capacitor plates = 20mm x 20mm = 400mm2 = 400 x 10-6m2
Voltage rating of capacitor = 500V
Now the capacitance of a capacitor is given by the formula:
C = Kє0 A/d
Where C= capacitance of capacitor in farad
K = dielectric constant
є0 = permittivity of free space = 8.854 x 10-12 Farad/m
d = separation of the capacitor plates
In this problem, since we are looking for dielectric constant, we make it the subject of formula thus:
K = Cd/ є0A
putting all our known values we have:
K = (2000 x 10-12 x 27 x 10-5)/(8.854 x 10-12 x 400 x 10-6) = 152.47 = 150 nearest approxSource(s): capacitance formula from: http://instrumenttoolbox.blogspot.com/search/label...
- renziLv 43 years ago
would be unable to reply to the Legality query for finished motor vehicle national, although that's unlawful in Oklahoma & Calipornia. As for the coolest judgment, i become shown a falling block single shot rifle geared up by (or for) the previous Western Scrounger while he become nevertheless in Montague, Ca. He reported that the guy desiring the rifle geared up meant on taking photos elk from mountain to mountain in Colorado. issue become that the rifle weighed in EMPTY at over sixteen pounds...