# Boyle's Law Calculations help?

I need Help on this problem.

A sample of gas occupies 2.50 L at 1.15 atm of pressure. What is the Volume at standard atmospheric pressure?

My teacher Game me the equation (P1)(V1)=(P2)(V2) and PV=K

I don't really know how to do the problem, setup ect. Can someone help me?

Relevance
• 10 years ago

Boyle's law states that the volume (v) of a gas and its pressure (p) are inversely proportional.

V= Constant/P

If we multiply both sides by P, we get: PV = Constant

This relationship is true because if the pressure increases, the volume decreases, but the product P x V is always equal to the same constant. For two different sets of condtions, we can say that

P1V1 = Constant = P2V2 or P1V1 = P2V2.

Where P1 and V1 are the initial pressure and volume of the gas, and P2 and V2 are the final volume and pressure.

Your problem is given: 2.50 L of a sample gas

1.15 atm of Pressure

Find: the volume of the atomosheric pressure

I am not sure if you have a third variable, but if not then you would use the formula of:

V(volume) = Constant divided by P (pressure)

Therefore, 2.50 L is your constant and 1.15 atm is the pressure.

2.50 L / 1.15 atm = 2.173913043 The average answer would be 2.17 using three significant figures for your answer.

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Lv 4
4 years ago

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