Anonymous
Anonymous asked in Science & MathematicsPhysics · 9 years ago

# Physics questions about magnetic fields and particles?

What speed must an alpha particle maintain if it is to remain suspended, relative to Earth’s surface, as it travels on a tangent to Earth’s surface and perpendicularly through Earth’s magnetic field of 50.0uT?

I could use some help with this. I have been staring at it and can't figure out where to go.Any help is appreciated, thanks.

Relevance

In order for the particle to be suspended, the magnetic force supporting it must balance the force of gravity pulling down.

Fnet=Fg-Fb=0N

Fg-Fb=0

Fg=Fb

mg=qvB(sin x)

since x is the angle compared to the magnetic field, and the question states this to be perpendicular, the angle (x) is 90. sin90=1, therefore we can get rid of it to make our algebra easier.

mg=qvB

v=mg/qB

where m is the particle's mass, g is the acceleration of gravity near the earth's surface, q is the particle's charge, and B is the strength of the magnetic field.

mass is the mass of two protons (an alpha particle is a helium nucleus, which consists of two protons).

m=2(1.673e-27) kg

g=9.8N/kg

the charge is the total charge of two protons

q=2(1.6e-19) C

B is the magnetic field, in this case, of the earth. This must be in Tesla.

B=50.0uT=50.0e-6 T

v=(9.8)*(1.673e-27)*(2)/(2)*(1.6e-19)*(50.0e-6)

=2.049425e-3 m/s

cheers.

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