Which has the most unpaired electrons, S+(a), S(b), S+(c)?

Which has the most unpaired electrons, S+(a), S(b), S+(c)?

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  • 10 years ago
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    a. S+

    The electronic configuration of S+ is [Ne] 3s2 3p3.

    Drawing the electron distribution for the 3p3 electrons for S+:

    X__--X__--X__ ----> 3 unpaired electrrons

    where: X represents the spin-up electrons

    b. S

    The electron configuration of S is [Ne] 3s2 3p4.

    Drawing the electron distribution for the 3p4 electrons for S:

    Xx_--X__--X__ ------> 2 unpaired electrons

    where:

    X represents the spin-up electrons

    x represents the spin-down electron

    b. S-

    The electron configuration of S- is [Ne] 3s2 3p5.

    Drawing the electron distribution for the 3p5 electrons for S-:

    Xx_--Xx_--X__ ------> 1 unpaired electron

    where:

    X represents the spin-up electrons

    x represents the spin-down electron

    Therefore, S+ has the most unpaired electrons.

    That's it!n_n

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