# Math help! *10 points!* Polynomials and Zeros?

I have the answers to these two problems in the back of the book, but I need to know HOW to do them. PLEASE help :)

*Find a polynomial function that has the given zeros:*

4, -3, 3, 0

and

*Find a polynomial of degree "n" that has the given zeros:*

(Zeros are -5, 0, 1) and (Degree is n=3)

### 3 Answers

- Davis PLv 79 years agoBest Answer
(x-4)(x+3)(x-3)(x-0)

x^4 -4 x^3 -9 x^2 +36 x

(x+5)(x)(x-1) = x^3 +4 x^2 - 5 x

- offerLv 43 years ago
For this actual issue 0's of the Polynomial ability the answer of 2x^2 - 8x + 6 = 0, or 2(x-a million)(x-3)=0, or the fee of x for which fee of the expression will become 0. for that reason if 2(x-a million)(x-3)=0 then it ability made from 2 , (x-a million) & (x-3) 0. considering 2 cant be equl to 0, so the two the fee of x-a million or that of x-3 = 0. which means that the two x=a million or 3. Thats it.

- Anonymous9 years ago
Since you have the zeros already you can easily find the function by going backwards from the zeros.

say:

X=4 subtract 4

X-4=0

X=-3 subtract -3

X+3=0

X=3 subtract 3

X-3=0

X=0 subtract 0

X-0=0 => X=0

now multiply those 4 equations to get the function.

f(X)=X(X-4)(X+3)(X-3)

that would be the function with those zeros.

same thing with this problem

X=-5

X+5=0

X=0

X=1

X-1=0

again multiply the zeros out

f(x)=X(X+5)(X-1)

expanding the function we get

f(x)=X^3 + 4X^2 - 5X

hope that helps