Math help! *10 points!* Polynomials and Zeros?

I have the answers to these two problems in the back of the book, but I need to know HOW to do them. PLEASE help :)

*Find a polynomial function that has the given zeros:*

4, -3, 3, 0

and

*Find a polynomial of degree "n" that has the given zeros:*

(Zeros are -5, 0, 1) and (Degree is n=3)

3 Answers

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  • 9 years ago
    Best Answer

    (x-4)(x+3)(x-3)(x-0)

    x^4 -4 x^3 -9 x^2 +36 x

    (x+5)(x)(x-1) = x^3 +4 x^2 - 5 x

  • offer
    Lv 4
    3 years ago

    For this actual issue 0's of the Polynomial ability the answer of 2x^2 - 8x + 6 = 0, or 2(x-a million)(x-3)=0, or the fee of x for which fee of the expression will become 0. for that reason if 2(x-a million)(x-3)=0 then it ability made from 2 , (x-a million) & (x-3) 0. considering 2 cant be equl to 0, so the two the fee of x-a million or that of x-3 = 0. which means that the two x=a million or 3. Thats it.

  • Anonymous
    9 years ago

    Since you have the zeros already you can easily find the function by going backwards from the zeros.

    say:

    X=4 subtract 4

    X-4=0

    X=-3 subtract -3

    X+3=0

    X=3 subtract 3

    X-3=0

    X=0 subtract 0

    X-0=0 => X=0

    now multiply those 4 equations to get the function.

    f(X)=X(X-4)(X+3)(X-3)

    that would be the function with those zeros.

    same thing with this problem

    X=-5

    X+5=0

    X=0

    X=1

    X-1=0

    again multiply the zeros out

    f(x)=X(X+5)(X-1)

    expanding the function we get

    f(x)=X^3 + 4X^2 - 5X

    hope that helps

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