How do I determine Avogadro's number with this information?
Using the volume, density and molar mass of carbon, determine Avogadro's number.
Density of C: 3.51
I just don't know how to use these numbers to arrive at the number. (note) the volume may be off because of experimental error, i just need to know the correct set up
- husoskiLv 79 years agoFavorite Answer
You could at least type in the units. The density figure looks like grams/cc density of diamond. The tiny size of the volume suggests that it the volume in cubic somethings occupied by an atom in whatever form of carbon you are looking at.
If so, and volume in cm^3 or cc units, then you have:
ρ = 3.51 g / cm^3
V = 2.60x10^-25 cm^3 / atom
M(C) = 12.01 g/mol
Multiplying ρV gives the mass of an atom in grams:
ρV = (3.51 g/cm^3) * (2.60 x 10^-25 cm^3 / atom) = 9.13 x 10^-25 g / atom
Avogadro's number N₀ is the number of atoms in a mole. Multiplying N₀ times the mass of an atom gives the mass of a mole of atoms, or:
ρVN₀ = M(C)
N₀ = M(C) / (ρV)
With your data, that's N₀ = (12.01 g/mol) / (9.13 x 10^-25 g/atom)
N₀ ~~ 1.32 x 10^25 atom/mol
That's well above 6.02x10^23, so either my guesses were bad or your data is lousy. That's an inclusive "or".
- cluttsLv 43 years ago
In chemistry and physics, the Avogadro consistent (symbols: L, NA) is defined using fact the ratio of the form of constituent debris (many times atoms or molecules) N in a pattern to the quantity of substance n (unit mole) during the dating NA = N/n.[a million] subsequently that's the proportionality ingredient that relates the molar mass of an entity, i.e. the mass according to volume of substance, to the mass of pronounced entity The Avogadro consistent expresses the form of user-friendly entities according to mole of substance and it has the fee 6.022c4ca4238a0b92382dcc509a6f75849b4c4ca4238a0b92382dcc509a6f75849b79(30)×c4ca4238a0b92382dcc509a6f75849b0^23 mol-a million.