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Chemistry and Gas Laws help PLEASE?!?
Find the volume, in liters, of each of the following at STP
a) 7.85g O2
b) 3.35g CO
c) 0.0159g H2S
d) 2.18 x 10^5 kg NH3
Thanks for your help!!!!!! :)
1 Answer
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- Lexi RLv 71 decade agoFavorite Answer
At STP (which is 0 deg Celcius and Pressure = 1 atm) 1 mole of any ideal gas occupies a volume of 22.4 L
So volume of a gas at STP = moles gas x 22.4 L/mol
a) moles = mass / molar mass
moles O2 = 7.85 g / 32.00 g/mol
= 0.2453125 moles
volume = 0.2453125 mol x 22.4 L/mol
= 5.495 L
= 5.50 L (3 sig figs)
Same method for all the others.
(Don't forget to convert the kg in the final question to g (1 kg = 1000 g))
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