AB and CD intersect at E. If measure of angleAEC=5x-20 and measure of angleBED=x+52, find measure of angleCEB?

I keep getting 116 but it's supposed to be 110 according to my book, can someone please give step by step instructions?

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  • flavy
    Lv 4
    10 years ago
    Favorite Answer

    angle AEC=angle BED from theorem in Geometry

    therefore;

    5x-20=x+52

    5x-x=52+20

    4x=72

    x=18

    therefore, angle AEC=BED=5(18)-20= 18+52= 70

    THE SUM OF ALL THE ANGLE =360

    360= angles, ( AEC+BED+CEB+AED)

    CEB=AED & AEC=BED

    360= 2(70) +2(CEB)

    CEB=[ 360-2(70)]/2 = 110

  • Anonymous
    10 years ago

    5x-20=x+52

    4x=72

    x=18

    measure of angle CEB=180-5*18-20=110

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