How many moles of N2 at STP?

how many moles of n2 gas occupy a volume of 11.2 liters at stp?

The equation is PV/RT=N right?

4 Answers

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  • Dr.A
    Lv 7
    10 years ago
    Favorite Answer

    At STP :

    pressure = 1 atm and T = 273 K

    n = pV/RT = 1 atm x 11.2 / 0.08206 x 273 =0.5

    because 0.08206 x 273 = 22.4

    the volume occupied by one mole at STP = nRT/p = 1 x 22.4 / 1 = 22.4

    this means that one mole of any gas at STP occupies 22.4 L

    so you can solve this question in this way

    moles = 11.2 L/ 22.4/L/mol= 0.5

    hope helps

  • Paul
    Lv 4
    10 years ago

    the usual symbol for amount in moles is n not N

    The trap with PV/RT is the units. SI base units are : Pascals, m3, J mol-1 K-1 and K

    More simply 1 mole of gas molecules at STP occupies 22.4 litres so you have .5 mol N2

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    4 years ago

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  • 4 years ago

    STP potential "usual Temperature and rigidity". This corresponds to 273K and 1atm. Use the equation PV = nRT, with the consistent R = 0.0821 (a million)V = (a million)(0.0821)(273) V = 0.0821 * 273 V = 22.4133L

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