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# How many moles of N2 at STP?

how many moles of n2 gas occupy a volume of 11.2 liters at stp?

The equation is PV/RT=N right?

### 4 Answers

- Dr.ALv 710 years agoFavorite Answer
At STP :

pressure = 1 atm and T = 273 K

n = pV/RT = 1 atm x 11.2 / 0.08206 x 273 =0.5

because 0.08206 x 273 = 22.4

the volume occupied by one mole at STP = nRT/p = 1 x 22.4 / 1 = 22.4

this means that one mole of any gas at STP occupies 22.4 L

so you can solve this question in this way

moles = 11.2 L/ 22.4/L/mol= 0.5

hope helps

- PaulLv 410 years ago
the usual symbol for amount in moles is n not N

The trap with PV/RT is the units. SI base units are : Pascals, m3, J mol-1 K-1 and K

More simply 1 mole of gas molecules at STP occupies 22.4 litres so you have .5 mol N2

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STP potential "usual Temperature and rigidity". This corresponds to 273K and 1atm. Use the equation PV = nRT, with the consistent R = 0.0821 (a million)V = (a million)(0.0821)(273) V = 0.0821 * 273 V = 22.4133L